waecmaths question:
Given that $P={{x}^{2}}+4x+2,\text{ }Q=2x-1\text{ and }Q-P=2$ find x
Option A:
–2
Option B:
–1
Option C:
1
Option D:
2
waecmaths solution:
$\begin{align} & P={{x}^{2}}+4x+2 \\ & Q=2x-1 \\ & P-Q=2 \\ & P-Q=({{x}^{2}}+4x+2)-(2x-1)={{x}^{2}}+2x+3=2 \\ & {{x}^{2}}+2x+1=0 \\ & {{(x+1)}^{2}}=0 \\ & x=-1 \\\end{align}$
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