waecmaths question:
For what value of y is the expression $\frac{6y-1}{{{y}^{2}}-y-6}$ not defined?
Option A:
$\tfrac{1}{6},\tfrac{1}{4}$
Option B:
3, –2
Option C:
–3, 2
Option D:
0, 1
waecmaths solution:
The expression $\frac{6y-1}{{{y}^{2}}-y-6}$will undefined when ${{y}^{2}}-y-6=0$$\begin{align} & {{y}^{2}}-y-6=0 \\ & (y-3)(y+2)=0 \\ & y=3\text{ or }y=-2 \\\end{align}$
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