Jambmaths question:
Simplify ${{(25)}^{-\tfrac{1}{3}}}\times {{(27)}^{\tfrac{1}{3}}}+{{(121)}^{-\tfrac{1}{4}}}\times {{(625)}^{-\tfrac{1}{4}}}$
Option A:
$\tfrac{14}{5}$
Option B:
$\tfrac{9}{11}$
Option C:
$\tfrac{3}{275}$
Option D:
$\tfrac{34}{55}$
Jamb Maths Solution:
$\begin{align} & {{(25)}^{-\tfrac{1}{2}}}\times {{(27)}^{\tfrac{1}{3}}}+{{(121)}^{-\tfrac{1}{2}}}\times {{(625)}^{-\tfrac{1}{4}}} \\ & {{({{5}^{2}})}^{-\tfrac{1}{2}}}\times {{({{3}^{3}})}^{\tfrac{1}{3}}}+{{({{11}^{2}})}^{-\tfrac{1}{2}}}\times {{({{5}^{4}})}^{-\tfrac{1}{4}}} \\ & {{5}^{-1}}\times 3+({{11}^{-1}})\times ({{5}^{-1}}) \\ & \frac{3}{5}+\frac{1}{11}\times \frac{1}{5}=\frac{3}{5}+\frac{1}{55}=\frac{33+1}{55}=\frac{34}{55} \\\end{align}$
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