Jambmaths question:
The sum of four consecutive integers is 34, find the least of these numbers
Option A:
8
Option B:
5
Option C:
6
Option D:
7
Jamb Maths Solution:
$\begin{align} & \text{Let the numbers be }n,n+1,n+2,n+3 \\ & \therefore n+n+1+n+2+n+3=34 \\ & 4n+6=34 \\ & 4n=24 \\ & n=6 \\ & \text{The least of the numbers is 6} \\\end{align}$
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