In the diagram PQRS is a circle, $\left| PT \right|=\left| QT \right|$ and $\angle QPT={{70}^{\circ }}$. What is the size of $\angle PRS$
40o
70o
80o
140o
$\begin{align} & \angle PQT=\angle QRT={{70}^{\circ }}\text{ }\!\!\{\!\!\text{ Base angles of Iss}\text{. }\vartriangle \text{ }\!\!\}\!\!\text{ } \\ & \angle PTQ={{180}^{\circ }}-\angle PQT-\angle QRT\text{ }\!\!\{\!\!\text{ Sum of }\angle s\text{ in a }\vartriangle \text{ }\!\!\}\!\!\text{ } \\ & \angle PTQ={{180}^{\circ }}-{{70}^{\circ }}-{{70}^{\circ }}={{40}^{\circ }} \\ & \angle STR=\angle PTQ={{40}^{\circ }}\text{ }\!\!\{\!\!\text{ Vertically opposite angles }\!\!\}\!\!\text{ } \\ & \left| ST \right|=\left| SR \right|\text{ }\!\!\{\!\!\text{ Radius of a circle }\!\!\}\!\!\text{ } \\ & \angle TSR=\angle SRT=x\text{ }\!\!\{\!\!\text{ Base angles of an isso }\vartriangle \text{ }\!\!\}\!\!\text{ } \\ & \angle STR+\angle TSR+\angle SRT={{180}^{\circ }}\text{ }\!\!\{\!\!\text{ Sum of }\angle s\text{ in a }\vartriangle \text{ }\!\!\}\!\!\text{ } \\ & \text{4}{{\text{0}}^{\circ }}+x+x={{180}^{\circ }} \\ & x={{70}^{\circ }} \\ & \angle SRT=\angle PRS={{70}^{\circ }} \\\end{align}$