waecmaths question:
In the diagram, RT is a tangent to the circle at R, $\angle PQR=70{}^\circ $, $\angle QRT=52{}^\circ $, $\angle QSR=y$ and $\angle PRQ=x$.Calculate the value of x
Option A:
70o
Option B:
58o
Option C:
55o
Option D:
48o
waecmaths solution:
$\begin{align} & \angle RPQ=\angle QSR=52{}^\circ \text{ }\!\!\{\!\!\text{ }\angle \text{s on the segment }\!\!\}\!\!\text{ } \\ & \vartriangle PQR+ \\ & \angle RPQ+\angle PQR+\angle PRQ=180{}^\circ \\ & 52{}^\circ +70{}^\circ +\angle PRQ=180{}^\circ \\ & \angle PRQ=58{}^\circ \\ & x=58{}^\circ \\\end{align}$
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