waecmaths question:
Express $\frac{2}{x+3}-\frac{1}{x-2}$ as a simple fraction
Option A:
$\frac{x-7}{{{x}^{2}}+x-6}$
Option B:
$\frac{x-1}{{{x}^{2}}+x-6}$
Option C:
$\frac{x-2}{{{x}^{2}}+x-6}$
Option D:
$\frac{x+7}{{{x}^{2}}+x-6}$
waecmaths solution:
$\frac{2}{x+3}-\frac{1}{x-2}=\frac{2(x-2)-(x+3)}{(x+3)(x-2)}=\frac{2x-4-x-3}{{{x}^{2}}+x-6}=\frac{x-7}{{{x}^{2}}+x-6}$
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