Jambmaths question:
Evaluate $\int_{0}^{\tfrac{\pi }{4}}{{{\sec }^{2}}\theta d\theta }$
Option A:
1
Option B:
2
Option C:
3
Option D:
4
Jamb Maths Solution:
$\begin{align} & \int_{0}^{\tfrac{\pi }{4}}{{{\sec }^{2}}\theta d\theta }=\left[ \tan \theta \right]_{0}^{\tfrac{\pi }{4}}=\tan \tfrac{\pi }{4}-\tan 0\text{ }\left| \tfrac{\pi }{4}radian={{45}^{\text{o}}} \right. \\ & \int_{0}^{\tfrac{\pi }{4}}{{{\sec }^{2}}\theta d\theta }=1 \end{align}$
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