waecmaths question:
If $p=\frac{1}{2}$ and $\frac{1}{p-1}=\frac{2}{p+x}$ , find the value of x
Option A:
–2 ½
Option B:
–1½
Option C:
1½
Option D:
2½
waecmaths solution:
$\begin{align} & \frac{1}{p-1}=\frac{2}{p+x} \\ & \frac{1}{\tfrac{1}{2}-1}=\frac{2}{\tfrac{1}{2}+x} \\ & \frac{1}{-\tfrac{1}{2}}=\frac{2}{\tfrac{1+2x}{2}} \\ & -2=\frac{4}{1+2x} \\ & -2(1+2x)=4 \\ & -2-4x=4 \\ & -4x=6 \\ & x=-\frac{6}{4}=-\frac{3}{2}=-1\tfrac{1}{2} \\\end{align}$
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