waecmaths question:
Find the smaller value of x that satisfies the equation ${{x}^{2}}+7x+10=0$
Option A:
–5
Option B:
–2
Option C:
2
Option D:
5
waecmaths solution:
$\begin{align} & {{x}^{2}}+7x+10=0 \\ & (x+5)(x+2)=0 \\ & x=-5\text{ or }x=-2 \\\end{align}$The least value is –5
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