waecmaths question:
A man’s eye level is 1.7m above the horizontal ground and 13m from a vertical pole. If the pole is 8.3m high, calculate, correct to the nearest degree, the angle of elevation of the top of the pole from his eyes
Option A:
33o
Option B:
32o
Option C:
27o
Option D:
26o
waecmaths solution:
$\begin{align} & \tan \theta =\frac{6.6}{13} \\ & \theta ={{\tan }^{-1}}(\tfrac{6.6}{13})=26.91 \\ & \theta \approx {{27}^{\circ }} \\\end{align}$
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