waecmaths question:
If c and k are roots of $6-x-{{x}^{2}}=0$, find c + k
Option A:
2
Option B:
1
Option C:
–1
Option D:
–3
waecmaths solution:
$\begin{align} & 6-x-{{x}^{2}}=0 \\ & 3(2-x)+x(2-x)=0 \\ & (3+x)(2-x)=0 \\ & x=-3,x=2 \\ & c+k=-3+2=1 \\\end{align}$
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