Jambmaths question:
A cylindrical tank has a capacity of 6160m3. What is the depth of the tank, if the radius of its base is 28m? [Take $\pi =\tfrac{22}{7}$]
Option A:
2.5m
Option B:
5.0m
Option C:
7.5m
Option D:
8.0m
Jamb Maths Solution:
$\begin{align} & volume=\pi {{r}^{2}}h \\ & 6160{{m}^{3}}=\frac{22}{7}\times {{28}^{2}}\times h \\ & h=\frac{6160\times 7}{22\times {{28}^{2}}}=2.5m \\\end{align}$
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