Jambmaths question:
Find the rate of change of the V of a sphere with respect to its radius r when r =1
Option A:
12π
Option B:
4π
Option C:
24π
Option D:
8π
Jamb Maths Solution:
$\begin{align} & v=\tfrac{4}{3}\pi {{r}^{3}} \\ & \frac{dv}{dr}=4\pi {{r}^{2}} \\ & \text{when }r=1 \\ & \frac{dv}{dr}=4\pi {{(1)}^{2}}=4\pi \\\end{align}$
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