waecmaths question:
Find the nth term of the sequence 2×3, 4×6, 8×9, 16×12
Option A:
${{2}^{n}}\times 3(n+1)$
Option B:
${{2}^{n}}\times 3n$
Option C:
${{2}^{n}}\times {{3}^{n}}$
Option D:
${{2}^{n}}\times {{3}^{n-1}}$
waecmaths solution:
$\begin{align} & 2\times 3,4\times 6,8\times 9,16\times 12 \\ & \text{We have two sequence here} \\ & 2,4,8,16,-,-,- \\ & nth\text{ term is }{{2}^{n}} \\ & 3,6,12,-,-,-, \\ & nth\text{ term is }3n \\ & \text{The }nth\text{ term of the sequence is }{{2}^{n}}\times 3n \\\end{align}$
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