waecmaths question:
If $\frac{2}{x-3}-\frac{3}{x-2}$is equal to $\frac{P}{(x-3)(x-2)}$ find P
Option A:
–x – 5
Option B:
–(x +3)
Option C:
(5x – 13)
Option D:
5 – x
waecmaths solution:
$\begin{align} & \frac{2}{x-3}-\frac{3}{x-2}=\frac{2(x-2)-3(x-3)}{(x-3)(x-2)} \\ & \frac{2}{x-3}-\frac{3}{x-2}=\frac{2x-4-3x+9}{(x-3)(x-2)} \\ & \frac{2}{x-3}-\frac{3}{x-2}=\frac{5-x}{(x-3)(x-2)} \\\end{align}$
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