waecmaths question:
In the diagram GI is a tangent to the circle at H. If $EF\parallel GI$ calculate the size$\angle EHF$
Option A:
126o
Option B:
72o
Option C:
54o
Option D:
28o
waecmaths solution:
$\begin{align} & \angle HFE=\angle FHI={{54}^{\circ }}\text{ }\!\!\{\!\!\text{ Alternate angele }\!\!\}\!\!\text{ } \\ & \angle HEF=\angle HFE={{54}^{\circ }}\text{ }\!\!\{\!\!\text{ opposite segments }\!\!\}\!\!\text{ } \\ & \angle EHF={{180}^{\circ }}-\angle HEF-\angle HFE \\ & \angle EHF={{180}^{\circ }}-{{54}^{\circ }}-{{54}^{\circ }}={{72}^{\circ }} \\\end{align}$
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