Jambmaths question:
A man 40m from the foot of tower observes the angle of elevation of the tower to be 30o. Determine the height of the tower
Option A:
40$\sqrt{3}$
Option B:
$\frac{40\sqrt{3}}{3}$
Option C:
40
Option D:
20
Jamb Maths Solution:
$\begin{align} & \tan {{30}^{\text{o}}}=\frac{h}{40} \\ & h=40\tan {{30}^{\text{o}}} \\ & h=\frac{40}{\sqrt{3}}=\frac{40\times \sqrt{3}}{\sqrt{3}\times \sqrt{3}}=\frac{40\sqrt{3}}{3} \\\end{align}$
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