Question 34

waecmaths question: 

Solve the equation 2x2x – 6 = 0

Option A: 

$x=-\tfrac{3}{2}\text{ or }2$

Option B: 

$x=-7\text{ or }\tfrac{3}{2}$

Option C: 

x = –3 or 2

Option D: 

x = 3 or – 2

waecmaths solution: 

$\begin{align}  & 2{{x}^{2}}-x-6=0 \\ & 2{{x}^{2}}-4x+3x-6=0 \\ & 2x(x-2)+3(x-2)=0 \\ & (2x+3)(x-2)=0 \\ & x=-\tfrac{3}{2}\text{ or }x=2 \\\end{align}$

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