Jambmaths question:
Find the value of x for which the function $f(x)=3{{x}^{2}}-x-6$ is minimum
Option A:
$-\tfrac{1}{6}$
Option B:
$\tfrac{1}{6}$
Option C:
$-\tfrac{73}{12}$
Option D:
$\tfrac{73}{12}$
Jamb Maths Solution:
$\begin{align} & f(x)=3{{x}^{2}}-x-6 \\ & f'(x)=6x-1 \\ & \text{At turning point }f'(x0=0 \\ & 6x-1=0 \\ & x=\frac{1}{6} \\ & f''(x)=6>0\text{(minimum point)} \\ & \text{At minimum point }x=\frac{1}{6} \\\end{align}$
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