waecmaths question:
Express $3-\left[ \frac{x-y}{y} \right]$ as a single fraction
Option A:
$\frac{3xy}{y}$
Option B:
$\frac{x-4y}{y}$
Option C:
$\frac{4y+x}{y}$
Option D:
$\frac{4y-x}{y}$
waecmaths solution:
$\begin{align} & 3-\left[ \frac{x-y}{y} \right]=\frac{3y-(x-y)}{y} \\ & =\frac{3y-x+y}{y} \\ & =\frac{4y-x}{y} \end{align}$
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