waecmaths question:
Simplify $\frac{\log \sqrt{8}}{\log 4-\log 2}$
Option A:
$\frac{2}{3}$
Option B:
$\tfrac{1}{2}\log 2$
Option C:
$\tfrac{3}{2}$
Option D:
$\log 2$
waecmaths solution:
$\frac{\log \sqrt{8}}{\log 4-\log 2}=\frac{\log {{8}^{\tfrac{1}{2}}}}{\log {{2}^{2}}-\log 2}=\frac{\tfrac{1}{2}\log {{2}^{3}}}{2\log 2-\log 2}=\frac{\tfrac{3}{2}\log 2}{\log 2}=\frac{3}{2}$
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