waecmaths question:
If ${{\log }_{a}}270-{{\log }_{a}}10+{{\log }_{a}}\tfrac{1}{3}=2$ what is the value of a?
Option A:
3
Option B:
4
Option C:
5
Option D:
6
waecmaths solution:
$\begin{align} & {{\log }_{a}}270-{{\log }_{a}}10+{{\log }_{a}}\tfrac{1}{3}=2 \\ & {{\log }_{a}}\frac{270\times \tfrac{1}{3}}{10}=2 \\ & {{\log }_{a}}9=2 \\ & {{a}^{2}}=9 \\ & {{a}^{2}}={{3}^{2}} \\ & a=3 \\\end{align}$
maths year:
maths topics: