$\begin{align}  & \frac{1}{\sqrt{3}+\sqrt{2}}=\frac{1}{\sqrt{3}+\sqrt{2}}\times \frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}-\sqrt{2}}=\frac{\sqrt{3}-\sqrt{2}}{3-2} \\ & \frac{1}{\sqrt{3}+\sqrt{2}}=\sqrt{3}-\sqrt{2} \\\end{align}$