waecmaths question:
Evaluate $7\tfrac{1}{2}-(2\tfrac{1}{2}+3)\div \tfrac{33}{2}$, correct to the nearest whole number
Option A:
33
Option B:
8
Option C:
7
Option D:
0
waecmaths solution:
$\begin{align} & 7\tfrac{1}{2}-(2\tfrac{1}{2}+3)\div \tfrac{33}{2}=\tfrac{15}{2}-(\tfrac{5}{2}+3)\times \tfrac{2}{33} \\ & 7\tfrac{1}{2}-(2\tfrac{1}{2}+3)\div \tfrac{33}{2}=\tfrac{15}{2}-(\tfrac{5+6}{3})\times \tfrac{2}{33} \\ & 7\tfrac{1}{2}-(2\tfrac{1}{2}+3)\div \tfrac{33}{2}=\tfrac{15}{2}-(\tfrac{11}{2}\times \tfrac{2}{33}) \\ & 7\tfrac{1}{2}-(2\tfrac{1}{2}+3)\div \tfrac{33}{2}=\tfrac{15}{2}-\tfrac{1}{3} \\ & 7\tfrac{1}{2}-(2\tfrac{1}{2}+3)\div \tfrac{33}{2}=\tfrac{45-2}{6}=\tfrac{43}{6}=7.1667 \\ & \text{To the nearest whole number} \\ & 7\tfrac{1}{2}-(2\tfrac{1}{2}+3)\div \tfrac{33}{2}\approx 7 \\\end{align}$
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