Jambmaths question:
From the diagram above, find the value of x correct to one decimal place
Option A:
20cm
Option B:
$\sqrt{304}cm$
Option C:
$\sqrt{108}cm$
Option D:
10cm.
Jamb Maths Solution:
$\begin{align} & \text{Using cosine rule} \\ & {{x}^{2}}={{8}^{2}}+{{12}^{2}}-2(12)(8)\cos {{120}^{\circ }} \\ & {{x}^{2}}=64+144+96=304c{{m}^{2}} \\ & x=\sqrt{304}cm \\\end{align}$
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