waecmaths question:
Given that Y is 20m on a bearing of 300o from X, how far south of Y is X?
Option A:
10m
Option B:
15m
Option C:
25m
Option D:
30m
waecmaths solution:
$XZ=20m\cos 60{}^\circ =20m\times \tfrac{1}{2}=10m$
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