waecmaths question:
In the diagram $\left| SQ \right|=4cm,\text{ }\left| PT \right|=7cm\text{, }\left| TR \right|=5cm$ and $ST\parallel QR$ If $\left| SP \right|=xcm$. Find the value of x
Option A:
5.6
Option B:
6.5
Option C:
6.6
Option D:
6.8
waecmaths solution:
$\begin{align} & \frac{\left| PS \right|}{PT}=\frac{\left| PQ \right|}{PR} \\ & \frac{x}{7}=\frac{4+x}{7+5} \\ & 12x=28+7x \\ & 5x=28 \\ & x=5.6 \\\end{align}$
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