waecmaths question:
PQRS is a square. If X is the midpoint of PQ, Calculate correct to the nearest degree, $\angle PXS$
Option A:
53o
Option B:
55o
Option C:
63o
Option D:
65o
waecmaths solution:
$\begin{align} & \tan \theta =\frac{opp}{adj}=\frac{a}{{a}/{2}\;} \\ & \tan \theta =2 \\ & \theta ={{\tan }^{-1}}2={{63.43}^{\circ }} \\ & \theta \approx {{63}^{\circ }}\text{ (to the nearest degree)} \\\end{align}$
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