waecmaths question:
The diagram show a circle centre O, If $\angle ZYW={{33}^{\circ }}$ Find $\angle ZWX$
Option A:
33o
Option B:
57o
Option C:
90o
Option D:
100o
waecmaths solution:
$\begin{align} & \angle ZYW=\angle ZXW={{33}^{\circ }}\text{ }\!\!\{\!\!\text{ Angles on the segment }\!\!\}\!\!\text{ } \\ & \angle WZX={{90}^{\circ }}\text{ }\!\!\{\!\!\text{ Angle subtended by a semicircle }\!\!\}\!\!\text{ } \\ & \text{Considering }\vartriangle WZX \\ & \angle ZWX+\angle WXZ+\angle WZX={{180}^{\circ }}\text{ }\!\!\{\!\!\text{ sum of angles in a triangle }\!\!\}\!\!\text{ } \\ & \angle ZWX+{{33}^{\circ }}+{{90}^{\circ }}={{180}^{\circ }} \\ & \angle ZWX={{57}^{\circ }} \\\end{align}$
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