Maths Question:
$\text{Differentiate }y={{x}^{\tfrac{2}{3}}}\text{ wrt }x$
Maths Solution:
$\begin{align} & y={{x}^{\tfrac{3}{2}}} \\ & \frac{dy}{dx}=\frac{3}{2}{{x}^{\tfrac{3}{2}-1}}=\frac{3}{2}{{x}^{\tfrac{1}{2}}} \\\end{align}$
University mathstopic: