Maths Question: $\text{Show that }\sin 6x-\sin 2x=2\cos 4x\sin 2x$ Maths Solution: $\sin 6x-\sin 2x=2\cos \tfrac{6x+2x}{2}\sin \tfrac{6x-2x}{2}=2\cos 4x\sin 2x$ University mathstopic: Trigonometry III
