Jambmaths question:
Solve the inequality $\tfrac{1}{2}x+\tfrac{1}{3}>\tfrac{1}{3}x+1$
Option A:
x < 6
Option B:
x > 7
Option C:
x > 7
Option D:
x < 4
Jamb Maths Solution:
$\begin{align} & \tfrac{1}{2}x+\tfrac{1}{3}>\tfrac{1}{3}x+1 \\ & \tfrac{1}{2}x-\tfrac{1}{3}x>1-\tfrac{1}{3} \\ & \tfrac{1}{6}x>\tfrac{2}{3} \\ & x>\tfrac{2}{3}\times \tfrac{6}{1} \\ & x>4 \\\end{align}$
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