waecmaths question:
Solve for x in the equation $\tfrac{3}{5}(2x-1)=\tfrac{1}{4}(5x-3)$
Option A:
0
Option B:
1
Option C:
2
Option D:
3
waecmaths solution:
$\begin{align} & \tfrac{3}{5}(2x-1)=\tfrac{1}{4}(5x-3) \\ & \text{Multiply both sides by }20 \\ & 12(2x-1)=5(5x-3) \\ & 24x-12=25x-15 \\ & -12+15=25x-24x \\ & 3=x \\ & x=3 \\\end{align}$
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