Jambmaths question:
Solve ${{x}^{2}}-5x+6\le 0$
Option A:
$-3\le x\le -2$
Option B:
$-2\le x\le -1$
Option C:
$1\le x\le 2$
Option D:
$2\le x\le 3$
Jamb Maths Solution:
${{x}^{2}}-5x+6\le 0$
$(x-2)(x-3)\le 0$
Testing for the range and validity
|
|
x$\le $ 2 |
2$\le $x$\le $3 |
x$\ge $ 3 |
|
(x-2) |
-ve |
+ve |
+ve |
|
(x-3) |
-ve |
-ve |
+ve |
|
product |
+ve |
-ve |
+ve |
From the above, the inequality is true within the range $2\le x\le 3$
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