Maths Question:
$\begin{align} & \text{Write down the general solution of the trigonometric equations} \\ & 2\cos ({{90}^{\circ }}-\theta )=\sqrt{2} \\\end{align}$
Maths Solution:
$\begin{align} & 2\cos ({{90}^{\circ }}-{{\theta }^{\circ }})=\sqrt{2} \\ & \cos ({{90}^{\circ }}-{{\theta }^{\circ }})=\frac{\sqrt{2}}{2} \\ & \cos ({{90}^{\circ }}-\theta )=\sin \theta =\frac{\sqrt{2}}{2} \\ & \theta ={{\sin }^{-1}}\frac{\sqrt{2}}{2}={{45}^{\circ }} \\ & \text{The general solution is }\theta =n{{180}^{\circ }}+{{(-1)}^{n}}({{45}^{\circ }}) \\\end{align}$
University mathstopic: