Jambmaths question:
Solve the inequality $-6(x+3)\le 4(x-2)$
Option A:
$x\ge -2$
Option B:
$x\le -1$
Option C:
$x\ge -1$
Option D:
$x\le 2
Jamb Maths Solution:
$\begin{align} & -6(x+3)\le 4(x-2) \\ & -6x-18\le 4x-8 \\ & -18+8\le 4x+6x \\ & -10\le 10x \\ & x\ge -1 \\\end{align}$
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