Jambmaths question:
Find the mean deviation of 1, 2, 3 and 4
Option A:
2.5
Option B:
2.0
Option C:
1.0
Option D:
1.5
Jamb Maths Solution:
$\begin{align} & mean=\bar{x}=\frac{1+2+3+4}{4}=\frac{10}{4}=2.5 \\ & mean deviation=\frac{\left| 1-2.5 \right|+\left| 2-2.5 \right|+\left| 3-2.5 \right|+\left| 4-2.5 \right|}{4} \\ & mean deviation=\frac{1.5+0.5+0.5+1.5}{4}=\frac{4}{4}=1 \\\end{align}$
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