waecmaths question:
In the diagram, $PQ\parallel RT$, $QR\parallel SU$, $\angle PQR={{48}^{\circ }}$AND find the value of x
Option A:
134o
Option B:
132o
Option C:
96o
Option D:
48o
waecmaths solution:
$\begin{align} & \angle QRT=\angle PQR=48 \\ & \angle RTU=\angle QRT={{48}^{\circ }}\text{ }\!\!\{\!\!\text{ Alternate angles }\!\!\}\!\!\text{ } \\ & \angle STR+\angle RTU={{180}^{\circ }}\text{ }\!\!\{\!\!\text{ Sum of }\angle s\text{ on a straight line }\!\!\}\!\!\text{ } \\ & X+{{48}^{\circ }}={{180}^{\circ }} \\ & X={{132}^{\circ }} \\\end{align}$
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