waecmaths question:
if (x – a) is a factor of $bx-ax+{{x}^{2}}-ab$, find the other factor
Option A:
(x + b)
Option B:
(x – b)
Option C:
(a + b)
Option D:
(a – b)
waecmaths solution:
$\begin{align} & bx-ab+{{x}^{2}}-ax=b(x-a)+x(x-a) \\ & =(b+x)(x-a) \\ & =(x+b)(x-a) \\\end{align}$
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