Maths Question:
$\begin{align} & \text{Write down the general solution of the trigonometric equations} \\ & \tan 3\theta =\sqrt{3} \\\end{align}$
Maths Solution:
$\begin{align} & \tan 3\theta =\sqrt{3} \\ & 3\theta ={{\tan }^{-1}}\sqrt{3} \\ & 3\theta ={{60}^{\circ }} \\ & \text{General solution } \\ & 3\theta =n{{180}^{\circ }}+{{60}^{\circ }} \\ & \theta =n{{60}^{\circ }}+{{20}^{\circ }} \\\end{align}$
University mathstopic: