waecmaths question:
In the diagram, PQRS is a parallelogram and $\angle QRT={{30}^{\circ }}$. Find x .
Option A:
95o
Option B:
100o
Option C:
120o
Option D:
150o
waecmaths solution:
$\begin{align} & \angle SRQ={{180}^{\circ }}-{{30}^{\circ }}\text{ }\!\!\{\!\!\text{ sum of angles on a straight line }\!\!\}\!\!\text{ } \\ & x=\angle SRQ={{150}^{\circ }}\text{ }\!\!\{\!\!\text{ opposite angle of parallelogram }\!\!\}\!\!\text{ } \\\end{align}$
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