Maths Question:
$\begin{align} & \text{Write down the general solution of the trigonometric equation} \\ & \sin (\theta +{{45}^{\circ }})=\frac{1}{2} \\\end{align}$
Maths Solution:
$\begin{align} & \sin (\theta +{{45}^{\circ }})=\frac{1}{2} \\ & \theta +{{45}^{\circ }}={{\sin }^{-1}}\frac{1}{2} \\ & \theta +{{45}^{\circ }}={{30}^{\circ }} \\ & \text{The general solution is} \\ & \theta +{{45}^{\circ }}=n{{180}^{\circ }}+{{(-1)}^{n}}({{30}^{\circ }}) \\ & \theta =[n{{180}^{\circ }}+{{(-1)}^{n}}({{30}^{\circ }})]-{{45}^{\circ }} \\\end{align}$
University mathstopic: