waecmaths question:
Factorize $({{x}^{2}}-2x-3xy+6y)$ completely
Option A:
$(x-2)(3x-y)$
Option B:
$(x-3y)(x-2)$
Option C:
$(x-2)(x+3y)$
Option D:
$(3x+y)(x-2)$
waecmaths solution:
$\begin{align} & ({{x}^{2}}-2x-3xy+6y)=x(x-2)-3y(x-2) \\ & =(x-3y)(x-2) \end{align}$
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