waecmaths question:
If ${{8}^{x+1}}=\frac{1}{4}$ fins x
Option A:
$-\tfrac{5}{3}$
Option B:
–1
Option C:
$-\tfrac{1}{3}$
Option D:
$\tfrac{1}{3}$
waecmaths solution:
$\begin{align} & {{8}^{x+1}}=\frac{1}{4} \\ & {{2}^{3(x+1)}}={{2}^{-2}} \\ & \text{Equating the base} \\ & 3(x+1)=-2 \\ & 3x+3=-2 \\ & 3x=-5 \\ & x=-\tfrac{5}{3} \\\end{align}$
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