waecmaths question:
Solve: $-\frac{1}{4}<\frac{3}{4}(3x-2)<\frac{1}{2}$
Option A:
$\frac{5}{6}<x<\frac{8}{9}$
Option B:
$-\frac{8}{9}<x<\frac{7}{9}$
Option C:
$-\frac{8}{9}<x<x\frac{5}{9}$
Option D:
$-\frac{7}{9}<x<\frac{8}{9}$
waecmaths solution:
$\begin{align} & -\frac{1}{4}<\frac{3}{4}(3x-2)<\frac{1}{2} \\ & -1<3(3x-2)<2\left| \text{Multiply both sides by 4} \right. \\ & -1<(9x-6)<2 \\ & 5<9x<8\left| \text{Add 6 to both sides of the inequality} \right. \\ & \frac{5}{9}<x<\frac{8}{9}\left| \text{Divide both sides of the inequality by }9 \right. \\ & \text{Option A} \\\end{align}$
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