waecmaths question:
Given that x = 2 and $y=-\frac{1}{4}$, evaluate $\frac{{{x}^{2}}y-2xy}{5}$
Option A:
0
Option B:
$\tfrac{1}{5}$
Option C:
1
Option D:
2
waecmaths solution:
$\frac{{{x}^{2}}y-2xy}{5}=\frac{{{2}^{2}}(-\tfrac{1}{4})-2(2)(-\tfrac{1}{4})}{5}=\frac{1-1}{5}=0$
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