waecmaths question:
Simplify$\frac{2-18{{m}^{2}}}{1+3m}$
Option A:
2(1+ 3m)
Option B:
2(1+3m2)
Option C:
2(1 – 3m)
Option D:
2(1 – 3m2)
waecmaths solution:
$\begin{align} & \frac{2-18{{m}^{2}}}{1+3m}=\frac{2(1-9{{m}^{2}})}{1+3m} \\ & \frac{2-18{{m}^{2}}}{1+3m}=\frac{2(1-3m)(1+3m)}{1+3m} \\ & \frac{2-18{{m}^{2}}}{1+3m}=2(1-3m) \end{align}$
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