waecmaths question:
If x : y : z = 2: 3: 4, evaluate $\frac{9x+3y}{6z-2y}$
Option A:
$1\tfrac{1}{2}$
Option B:
2
Option C:
$2\tfrac{1}{2}$
Option D:
3
waecmaths solution:
$\frac{9x+3y}{6z-2y}=\frac{9(2)+3(3)}{6(4)-2(3)}=\frac{18+9}{24-6}=\frac{3}{2}=1\tfrac{1}{2}$
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