waecmaths question:
Evaluate (0.13)3 correct to three significant figures.
Option A:
0.00219
Option B:
0.00220
Option C:
0.00300
Option D:
0.00390
waecmaths solution:
$\begin{align} & {{0.13}^{3}}=0.13\times 0.13\times 0.13 \\ & {{0.13}^{3}}=1.3\times {{10}^{-1}}\times 1.3\times {{10}^{-1}}\times 1.3\times {{10}^{-1}} \\ & {{0.13}^{3}}=2.197\times {{10}^{-3}} \\ & {{0.13}^{3}}=0.002197 \\ & 0.13\approx 0.00220\text{ to 3s}\text{.f} \\\end{align}$
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